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0.07x^2+0.06x-375=0
a = 0.07; b = 0.06; c = -375;
Δ = b2-4ac
Δ = 0.062-4·0.07·(-375)
Δ = 105.0036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{105.0036}}{2*0.07}=\frac{-0.06-\sqrt{105.0036}}{0.14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{105.0036}}{2*0.07}=\frac{-0.06+\sqrt{105.0036}}{0.14} $
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